The evolution of the universe is a continuous evolving process, implying that the 3D world of which we are a part is not static but dynamic.
The concept of Time, is a typical human related concept based on the idea that we can remember what has happened in the part and we can predict the future. This happens because we have a brain. Animals also have this capability, but it is less develloped.
Simply described, the capabilty to remember, is based on storing 3D images of our surroundings. The different images are identical of what you can call the time component in our existance. This component is not something personal but related to the whole of the universe. The present image which shows the whole of the universe we call: now. The previous images we call the past and expected images the future.
It is only the present moment that exist. The present nor the future exist.
In order to classify the images we use a clock. A clock is some sort of oscillator. Each count represent an image but infact any number of images can be considered inbetween two counts.
It is important that a clock or oscillator is a physical process and its behaviour can be subject of change or movement.
B
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t1/ |t2 \t1
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/ | \
/ | \
-C--------A--------D-
v1 v1
Figure 1 - l=v1*t1
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B
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/|\
/ | \
/ | \
/ | \
t1/ |t2 \t1
/ | \
/ | \
/ | \
-C--------A--------D-
v2 v2
Figure 2 - l=v2*t2
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B
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^ /^\ ^
. / | \ .
. / | \ .
. / | \ .
. / |t2 \ .
. / | \ .
. / | \ .
./ | \.
-C--------A--------D-
v2 v2
Figure 3 - l=v2*t2
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- Both Figure 1 and Figure 2 show a clock based on light signals.
- There is one light signal which moves from A to B, is reflected, and goes back to A. This signal represents a point at rest and the duration is t2. The length of AB = c * t2 with c the speed of light.
- There is one light signal which moves from C to B, is reflected and detected at point D. This signal represents a moving point and the total duration is 2 * t1. The length of CB (BD) = c * t1 with c the speed of light.
- Using CA = AD = l we come to the following equation: (c * t1)^2 = (c * t2)^2 + l^2 (1)
or t1^2 = t2^2 + (l/c)^2 or that t1>t2
This means, considering a fixed duration, that the number of ticks with the moving clocks (the light path CBD) is less than the number of ticks with the clock at rest (the light path ABA)
This is true for both Figure 1 and Figure 2
However there is also a difference between figure 1 and Figure 2.
- In Figure 1 the speed v of the moving object is expressed as a function of t1.
That means l = v1 * t1
Inserting that in equation 1 we get: (c * t1)^2 = (C * t2)^2 + (v1 * t1)^2
Or: (c^2 - v1^2) * t1^2 = c^2 * t2^2 or t1 = t2 * sqrt(c^2/(c^2 - v1^2)
Or with v1 = v we get t1= t2 *sqrt (1/ (1 - v^2/c^2)). (2)
This means also that t1>t2
- In Figure 2 the speed v of the moving object is expressed as a function of t2.
That means l = v2 * t2
Inserting that in equation 1 we get: (c * t1)^2 = (C * t2)^2 + (v2 * t2)^2
Or: c^2 * t1^2 = (c^2 + v2^2)* t2^2 or t1 = t2 * sqrt(1 + v2^2/c^2)
Or with v2 = v we get t1= t2 *sqrt (1 + v^2/c^2)). |
width = 20%> (3) |
This means also that t1>t2
Figure 1 is the simplest. One light signal is involved. Starting from C, reflecting at B and endding at D. The distance of the object is 2*l. The duration of the lightpath is 2*t1 and the speed v1 = 2 * l/2 * t1 = l/t1.
Figure 2 is much more complex. Because using a certain reasoning, three lightsignals or clocks are involved as shown in Figure 3. There is a clock at point C, point A and point D. All the clocks start simultaneous. They all are reflected simultaneous against the mirror and they all reach the bottom simultaneous.
The time measured by the clock at A is t2 and the distance moved by the object is l.
The time measured by the clcok at D is 2t2 and the distance moved by the object is 2l.
In both cases the speed by the object is 2l/2t2 = l/t2 = v2.
In fact that is the most difficult part of this experiment. You have an object which moves from C to D, with a certain speed, but how is this speed calculated. Figure 1 and Figure 2 show two different answers. General speaking you need two clocks, one at the start and one at the finish, which should run simultaneous. Both clocks should be synchronised. The physical aspect of these clocks is, that they should not move, because if they move, they run slower. This is the result of the whole experiment.
The conclusion is that a clock is a physical process and depending about its speed, compared with a clock at rest, can run faster or slower. What is more only clocks at rest should be used when speeds or accelarations are considered.
However the observation that a clock can run faster or slower, has nothing to do of what you can call the physical age of the universe. This age increases at a constant 'speed'
What is even more, the reaction rate of a process can be influenced by the particles involved. This can be the case for radioactive processes, when alpha or beta particles are emitted. This by itself can be an indication how long the process took place, but has no consequence related to the aging of the universe.